Tutorial_8 solutions (1)

34 - three-dimensional F1 = 39i + 79j + 246k F2= 135i - 253j + 82k   for vectors F1 + F2 =? do the collection.A) 174i - 174j + 328kB) 106i - 17j + 112kC) 154i - 49j + 160kD) 666i - 593j - 43kE) 121i + 62j + 117k

7 6.2/ A vertical double acting steam engine develops 75 kW at 250 r.p.m. The maximum fluctuation of energy is 30 per cent of the work done per stroke. The ximum and minimum speeds are not to vary more than 1 per cent on either side the mean speed. Find the mass of the flywheel required. if the radius of gyration m . oaw nd g %fifl@;:%m Is

An undamped spring/mass system, in which m = 8 slugs and the spring constant k = 16 lb/ft has a driving force f(t) = t^pi*t on [0,pi] Extend f(t) into the negative t-axis to obtain an odd function. Find the particular solution ??(?). (Note: f(t) is given as half of the period, p = π.)

Şekildeki parçalar birbirine M8-4.6 halite 4 cıvata ile bağlanmıştır. sürtünme katsayıları μ = 0.15 μs = 0.2 alınacaktır. 10000 Newton yükün sürtünmeyle taşınması için cıvataların ne kadar tork sıkılması gerekir. (Kaymaya karşı% 50 güvenlik gereklidir.)

der engine has been drawn 0 2 moment diagram for a multicylin ~ 2.4° horizontallv. e = 4500 N-m vertically and 1 mm 'mxemapwd areas between output torque curve and the mean resistance line taken in order from one end are 342. 23, 245. 303. 115. 232. 227. 164 mm2. when the engine is running at 150 r.p.-m- If the mass of the flywheel is 1000 kg and the tota! fluctuation of speed does not exceed 3% of the mean speed. find the minimum value of the radius of gyration 16.4/ The turning

A driven damped oscillator has k = 32.0 N/m, m = 0.5 kg and b = 1Ns/m. If F(t)=F0 cos ωt with F0 = 10N is the oscillator's driving force and ω= 2ω0 where ω0 is its natural frequency. Solve for the initial conditions x(t=0) = 2m and v(t=0) = 0 using a differential equation method.

Answers (a) er=15.30-250.2/r^2 , etheta=15.30+250.2/r^2 (b) delta c = 8.12x10^-4 in

The turning moment diagram for a multi cylinder engine has been drawn toa scale of 1 mm = 4500 N -m vertically and 1 mm = 2. 4 ͦ horizontally. Theintercepted areas between output torque curve and mean resistance lineabove and below the mean taken in order from one end are 342, 23, 245,303, 115, 232, 227, 164 ??2, when the engine is running at 150 rpm. Ifthe mass of the flywheel is 1000 kg and the total fluctuation of speed doesnot exceed 3% of the mean speed, find the minimum value of the radius ofgyration.

Three series springs have stiffness constant of 100 N/m each. Determine the spring stiffness equivalent of the springs.   a.)100 N/m b.)300 N/m c.)0.01 N/m d.)33.3 N/m

The reaction 2I- (aq) + S2O82- (aq) → I2 (aq) + 2SO42- (aq) was studied at 25°C. The following results were obtained where Rate = - (Δ[S2O82-])/(Δt)   [I-]0(mol/L) [S2O82-]0(mol/L)   Initial Rate (mol/L ·s) 0.080 0.040 12.5 x 10-6 0.040 0.040 6.25 x 10-6 0.080 0.020 6.25 x 10-6 0.032 0.040 5.00 x 10-6 0.060 0.030 7.00 x 10-6   a. Determine the rate law. b. Calculate a value for the rate constant for each experiment and an average value for the rate constant

The Euler’s theory holds good for ________ Select one: a. Long column b. Short column c. Short shaft d. Long shaft

A 25 kg mass is attached to a spring with spring constant 100 N/m. The mass is driven by an external force equal tof(t) = 5 cos(2t). The mass is initially released from rest from a point 1 m below the equilibrium position. (Use theconvention that displacements measured below the equilibrium position are positive.) Write the initial-value problem which describes the position of the mass.

22-A flywheel of mass 0.7 ton is fitted to a multi cylinder engine, which runs at a mean speed of 400 r.p.m. If the speed varies from 7 % above the mean to 3 % below it and the fluctuation energy is 2100 kN-cm, find (i) mass moment of inertia of the wheel and (ii) radius of Gyration.                                        Solution: The mass moment of Inertia in Kgm2 is Radius of Gyration in m is

The end of a spring is pulled to the right by 4 cm; the restoring force is8 N to the left. Given the relationships 8.15c, if the spring is returned to equilibrium and then pushed to the left by 2 cm, the restoring force isA. 4 N to the left.         B. 4 N to the right.         C. 8 N to the left.D. 8 N to the right.      E. 16 N to the left.          F. 16 N to the right.

A test carried out on a one-cylinder engine that works based on the Otto cycle, gives the following data: moment of rotation or torque = 950N-m; mean effective pressure = 758kPa; inner diameter = 30cm: stroke = 32cm; spin speed = 320rpm; fuel consumption = 0.003 kg / sec; calorific value of fuel = 42000kJ / kg. Determine: a) The thermal efficiency of the motor; b) mechanical efficiency; c) the fuel limit per hour if it has a price of 18.5 pesos per liter. Its relative density is 0.82

A helical compression spring is required to provide a minimum force of 150 lb at installation and have a working deflection of 1 in. The spring rate is 75 lb/in. The coil must fit in a 2.1-in-dia hole with 0.1 in total clearance. Use 0.25-in diameter unpeened music wire and squared/ground ends. Use a 15% clash allowance, shear modulus G = 11.5 Mpsi, and weight density γ = 0.285 lb/in3. Assume Sys = 0.6Sut. Part A Find the shear stress at the initial deflection. Express your answer in pounds per square inch to three significant figures.         τiτi =       Part B Find the mean stress. Express your answer in pounds per square inch to three significant figures.     Part C Find the alternating stress in the coil. Express your answer in pounds per square inch to three significant figures.     Part D Find the fatigue safety factor for infinite life in shear. Express your answer using three significant figures.…

A truck and trailer must be able to accelerate at 0.3 m/s2 up an incline of 1 in 20. The truck’s engine generates a torque of 900Nm. It has a moment of inertia of 30kg.m2 . The efficiency of the truck’s transmission is 83%. The mass of the truck is 12 tons, and that of the trailer is 9tons. The tractive resistance for both the truck and the trailer combined is 60N/ton. The truck has 12 wheels and the trailer has 8 wheels. The wheels on both vehicles are identical. Each wheel has a diameter of 1.2m, a mass of 75kg and a radius of gyration of 500mm. Determine two suitable overall gear ratios.

In case of a single cylinder double acting steam engine, 180 kW power is being developed at a mean speed of 120 r.p.m. The coefficient of fluctuation of energy is 0.12. The fluctuation of speed is ± 2% of mean speed. The flywheel rim has mean diameter of 2 metre. The hub and spokes of the flywheel provide 8% of the rotational inertia of the flywheel. If the density of the flywheel material is 7200 kg/m3, determine the mass and cross-sectional area of the flywheel rim.

A uniform Simply-supported beam is found to vibrate in its first mode with the amplitude of 12 mmat its center. Assume E=200 GPa, 4 1000I mm= , 3 7500, kgm= 2 50 A mm = and L=2 m.Determine the maximum bending moment in the beam. Also find the first three naturalfrequencies.

19 - A) 4000 NB) 8000 NC) 24 000 ND) 6000 NE) 10 000 N

Piston (M=5kg) is driven when the fly wheel (r=0.1m, J=0.5kgm^2) moves the arm (L=0.2m,m=1kg). The stiffness k=100N/m come Fron compression of gas. What is the natural frequency of the system

A flywheel  is fitted to a multi cylinder engine, which runs at a mean speed of 360 r.p.m. If the speed varies from 6 % above the mean to 2 % below it and the fluctuation energy is 1200 kN-cm, If the radius of gyration is 20 cm, find (i) mass moment of inertia of the wheel and (ii) mass of flywheel. The mass moment of Inertia in Kgm2 is Mass of the flywheel in kg is

3kg mass. P= 155N and w=0

27-(a) A body of weight 440 N body moving to the left with a velocity of 10 m/s collides with another body of weight 760 N body which is at rest. After impact the body which is moving before impact comes to rest. Find the final velocity of  body after impact and the coefficient of restitution .                                  (b)A vehicle of mass 21 tonnes runs into a buffer stop having two buffer springs connected in series each of 1750 kN/cm and 2200 kN/cm stiffness respectively. Find the maximum compression of the springs, if the vehicle is travelling at 90 km/hr. Also calculate the load acting on the spring.                  a,Solution The final velocity of  body after impact in m/s is The coefficient of restitution is b,Solution The maximum compression of the spring in mm is The load acting on the spring in kN is

ᴀɴ ᴀᴍᴍᴏɴɪᴀ ᴄᴏᴍᴘʀᴇꜱꜱᴏʀ ᴏᴘᴇʀᴀᴛᴇꜱ ᴀᴛ ᴀɴ ᴇᴠᴀᴘᴏʀᴀᴛᴏʀ ᴘʀᴇꜱꜱᴜʀᴇ ᴏꜰ 316 ᴋᴘᴀ ᴀɴᴅ ᴀ ᴄᴏɴᴅᴇɴꜱᴇʀ ᴘʀᴇꜱꜱᴜʀᴇ ᴏꜰ 1514.2 ᴋᴘᴀ. ᴛʜᴇ ʀᴇꜰʀɪɢᴇʀᴀɴᴛ ɪꜱ ꜱᴜʙᴄᴏᴏʟᴇᴅ 5 ᴅᴇɢʀᴇᴇꜱ ᴀɴᴅ ɪꜱ ꜱᴜᴘᴇʀʜᴇᴀᴛᴇᴅ 8 ᴅᴇɢʀᴇᴇꜱ. ᴀ ᴛᴡɪɴ-ᴄʏʟɪɴᴅᴇʀ ᴄᴏᴍᴘʀᴇꜱꜱᴏʀ ᴡɪᴛʜ ʙᴏʀᴇ ᴛᴏ ꜱᴛʀᴏᴋᴇ ʀᴀᴛɪᴏ ᴏꜰ 0.85 ɪꜱ ᴛᴏ ʙᴇ ᴜꜱᴇᴅ ᴀᴛ 1200 ʀᴘᴍ. ᴛʜᴇ ᴍᴇᴄʜᴀɴɪᴄᴀʟ ᴇꜰꜰɪᴄɪᴇɴᴄʏ ɪꜱ 77%. ꜰᴏʀ ᴀ ʟᴏᴀᴅ ᴏꜰ 87.5 ᴋᴡ, ᴅᴇᴛᴇʀᴍɪɴᴇ: (ᴀ) ᴛʜᴇ ᴠᴏʟᴜᴍᴇ ꜰʟᴏᴡʀᴀᴛᴇ ᴏꜰ ᴄᴏᴏʟɪɴɢ ᴡᴀᴛᴇʀ ɪɴ ᴛʜᴇ ᴄᴏɴᴅᴇɴꜱᴇʀ ɪꜰ ᴛʜᴇ ɪɴᴄʀᴇᴀꜱᴇ ɪɴ ᴛᴇᴍᴘᴇʀᴀᴛᴜʀᴇ ɪꜱ 7 ᴅᴇɢʀᴇᴇꜱ, (ʙ) ᴛʜᴇ ʙᴏʀᴇ ᴀɴᴅ ꜱᴛʀᴏᴋᴇ, (ᴄ) ᴛʜᴇ ꜱɪᴢᴇ ᴏꜰ ᴛʜᴇ ᴅʀɪᴠɪɴɢ ᴍᴏᴛᴏʀ, ᴀɴᴅ (ᴅ) ᴛʜᴇ Qᴜᴀʟɪᴛʏ ᴏꜰ ᴛʜᴇ ʀᴇꜰʀɪɢᴇʀᴀɴᴛ ᴇɴᴛᴇʀɪɴɢ ᴛʜᴇ ᴇᴠᴀᴘᴏʀᴀᴛᴏʀ

ANSWERS W6/T1 (a) 0.23 m/s (b) 0.13 m/s (c) 1.16 m/s (d) 0.22 m/s   show working how to reach these please

ASAPq=40 /p=4

Under the action of a torsional moment of 3880 kg.cm, a transmission shaft undergoes an angular deformation of 0.25º / m. knowing that its length is 1200 mm and that the material used in its construction is a 1045 hot-rolled steel, it is requested:a) The diameter of the tree.b) Disregarding the angular deformation and with the diameter calculated in the previous item, what is the transmissible power at 120 rpm.Data: G = 8 x 104 kg / cm²; e X = πR4 / 2

A mechanism used in printing machinery consists of a tension spring assembled with a preload of 40 N. The mean diameter of the coilis 32 mm with a spring index of 8. The spring has 18 active coils. The spring wire is hard drawn and oil tempered having the following material properties: a.Design shear stress = 700 MPb b. .Modulus of rigidity = 80 kN/mm2 Identify  (a) the initial torsional shear stress in the wire, (b) the spring rate, and (c) the force to cause the body of the spring to reach its yield strength.

Total Load = 40 + 150 + 100 + 60 + 40 = 390KNRD = 217.62 RB = 172.38 Don't skip solutions thanks!